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 Originally Posted by Rambam77
You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76.
AK(12) 4-A left x 3-K left in the deck
AQ(16) 4-A left x 4- Q left in the deck
AA(6) using 6310 method no A showing leaving 6 combos
KK(3) using the 6310 method 1 K is showing leaving 3 combos
A8(8) 4-A left x 2-8 left in the deck
76(12) 3-7 left x 4-6 left in the deck
 Originally Posted by Cobra_1878
You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76.
AK - 4 As and 3 Ks (4*3) = 12 combos.
AQ - 4 As and 4 Qs (4*4) = 16 combos.
AA - Using 6310 = 6 combos of AA.
KK - Using 6310 = 3 combos of KK.
A8 - 4 As and 2 8s (4*2) = 8 combos.
76 - 3 7s and 4 6s (3*4) = 12 combos.
Good job guys. I know that this is something that some people have seen before, but it's pretty critical to be able to do this, and that's why I've included it as the first lesson.
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