You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76.
AK(12) - Four Aces, & Three Kings left in the deck - 3*4=12
AQ(16) - Four Aces, & Four Queens left in the deck - 4*4=16
AA(6) - 6310, No Aces blocked - 6
KK(3) - 6310, One King blocker - 3
A8(8) - Four Aces, & Two Eights left in the deck - 4*2=8
76(12) - Three Sevens, & Four Sixes left in the deck - 3*4=12