**Ask a monkey a physics question thread**

Originally Posted by OngBonga

Thanks for this analysis, I'll get back to you when the weather perks up again and I put this into action!

Keep in mind that you don't want that evaporated water in the room. It bears the energy and keeping that energy out is kinda the point.

It's important that the water is evaporated by energy taken from the room. Adding an energy source to evaporate the water kinda eliminates the point.

Keep me posted. You'll want a cool room while you setup your pilot wave detector.

04-13-2017 08:59 AM #1
OngBonga View Profile View Forum Posts Private Message View Blog Entries Join Date Jul 2010 Posts 25,005 Location England	Originally Posted by MadMojoMonkey It takes 40.66 kJ/mol of water... Thanks for this analysis, I'll get back to you when the weather perks up again and I put this into action!
	Originally Posted by wufwugy ongies gonna ong
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04-18-2017 11:41 PM #2
MadMojoMonkey View Profile View Forum Posts Private Message View Blog Entries AINT SHOVELING SHIT Join Date Apr 2012 Posts 10,456 Location St Louis, MO	Originally Posted by OngBonga Thanks for this analysis, I'll get back to you when the weather perks up again and I put this into action! Keep in mind that you don't want that evaporated water in the room. It bears the energy and keeping that energy out is kinda the point. It's important that the water is evaporated by energy taken from the room. Adding an energy source to evaporate the water kinda eliminates the point. Keep me posted. You'll want a cool room while you setup your pilot wave detector.

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