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Re: Why you can't bet to give yourself better pot odds!
Your not betting just so that a call is +EV, in this situation your betting because betting is +ev. And then when you are faced with the raise, the call is also +ev. Therefore, you make both decisions. Like I was saying, the ev of your bet and the ev of your call is separate of one another.
 Originally Posted by loonychune
In this case, the raised pot totals $16 ($10 + $2 you add + $4 opponent puts in) and it costs you $2 to call -- that's 12.5% pot equity and you have 20% equity to win! But...
Not sure how many more times I will quote this paragraph, but anyways. Can you explain where "12.5%" comes from? If the pot is $16 and it costs you $2 to make a call, then you need:
Ev(2call) = (amount to call) / (pot + amount to call)
Ev(2call) = (2) / (16 + 2)
Ev(2call) = 2/18 = 0.1111111 or 11%
Therefore, you need 11% equity in the pot to make a breakeven call. Given you have more than the needed equity in this situation, then a call is +ev.
I would just like to note, that it wasn't you that gave yourself correct odds to call, it was villain. His raise size just laid you too good of odds to pass up on. Had villain raised to a reasonable amount, then a call from you would have been -ev; however, the bet you made would have still be +ev. For example,
You have 20% equity. The pot is $10. You bet $2, and villain raises to $9 (calling your $2 and putting in $7 more). The pot is now $21 and you must call $7.
Ev(call) = (equity)(total pot) - (what it cost)
Ev(call) = (0.20)(28) - (7)
Ev(call) = -$1.40
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