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  1. #11
    Quote Originally Posted by MadMojoMonkey View Post
    We can now write out a sine equation for the angle a/2.
    sin(a/2) = {opposite}/{hypoteneus}
    sin(a/2) = (c/2)/R
    sin(a/2) = c/(2R)
    a/2 = arcsin(c/(2R))

    a = 2arcsin(c/(2R))
    Ok am I right in thinking that the arcsin is basically the inverse, or reciprocal, of sin?

    Also...

    So the arc length is
    R*a = 2R*arcsin(c/(2R))
    Where's pi? It's not c/2r because c here is chord, not circumference.
    Last edited by OngBonga; 05-12-2016 at 09:28 AM.
    Quote Originally Posted by wufwugy View Post
    ongies gonna ong

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