[5NL] JJ, IP, 3bet pot, river spot.

[Savy]

How do you work that out? I thought it was pot ($1.27) + villain's bet (0.35) + my call (0.35).

$1.27 + 0.35 + 0.35 = $1.97? Or am I missing something?

Unless I have to raise $1.97 on top of my 0.35 call?

The pot includes villains bet though.

So it's $1.62 (which is $1.27 +0.35) + $0.70 = $2.32

[Cobra_1878]

The pot includes villains bet though.

So it's $1.62 (which is $1.27 +0.35) + $0.70 = $2.32

No it doesn't? The pot on the flop, before any action is taken is $1.27, then villain bets 0.35 making it $1.62, plus my call making it $1.97???

Can someone clear this up please coz am lost now.

EDIT - I think I got it now. Pot is $1.27, villain bets 0.35 making it $1.62. I call that bet, before I raise, making pot $1.97. I can now raise a further $1.97 as that is what the current pot is at. Making my PSR $2.32.

[Savy]

No it doesn't? The pot on the flop, before any action is taken is $1.27, then villain bets 0.35 making it $1.62, plus my call making it $1.97???

Can someone clear this up please coz am lost now.

Say you are the first to act. Let the pot size be P.

A pot sized bet is P.
Making the pot now P+P = 2P
Your opponent has to call P.
So your opponent has to put in 1/3 of the money of the pot.
(P is 1/3 of 3P)

This is proof that in a heads up situation a pot sized raise should always result in your opponent having to call a total of 1/3 of the final pot.


What You Said
If your opponent acts first and bets B into a pot P then the pot is now P+B.

If you bet P+B+B = P+2B

The pot is now 2P+3B

You have raised by P+B (to P+2B) so your opponent has to call P+B.

This makes the total pot 2P+3B + P+B = 3P+4B

P+B =/= 1/3(3P+4B) (it is less than)


What I said
Pot is P+B (same as before)
You raise to P+3B
The pot total is now P+B + P+3B = 2P+4B

Your opponent has to call P+3B - B = P+2B (Your raise minus his bet)

P+2B = 1/3 (3P+6B)

Which is a pot sized raise.

[Cobra_1878]

Say you are the first to act. Let the pot size be P.

A pot sized bet is P+P = 2P and your opponent has to call P. So your opponent has to put in 1/3 of the money of the pot. (P is 1/3 of 3P)


If your opponent acts first and bets B into a pot P then the pot is now P+B.

If you bet P+B+B then the total pot is now 2P+3B

You have raised by P+B (to P+2B) so your opponent has to call P+B.

P+B =/= 1/3(3P + 4B)


However if the pot is P+B (same as before) and you raise to P+3B then the pot is now 2P+4B.

Your opponent has to call your raise of P+2B (as he already has B in)

P+2B = 1/3 (3P+6B)

Which is a pot sized raise.

Not a chance of me understanding a single thing you just wrote. I hate it when letters are used in equations. Just use numbers, makes life so much easier.

[MadMojoMonkey]

EDIT - I think I got it now. Pot is $1.27, villain bets 0.35 making it $1.62. I call that bet, before I raise, making pot $1.97. I can now raise a further $1.97 as that is what the current pot is at. Making my PSR $2.32.

Should've left this part of the discussion right here. This is the max amount you can bet in a pot limit game.