Why is shoving
turn be a better play? I decided to perform some detailed calculation to illustrate my point.
Assume 1)
villain was not folding his TP (AK, AQ or AJ) on the
turn, which was a reasonable assumption coz there would be 12.50 in the pot and
villain would have 12.75
behind (and that this was micro NL25). 2) Also assume that
villain and I had equal stacks ($17.25 each) and 3) assume that we were heads-up already preflop (makes the maths easier).
My hand (T2) is a 72.9% favorite if we got
all-in on
flop. Hence my PE would be 35.5 * 0.729 = 25.89.
If I just
call flop 5 things can happen on 45 possible turns:
28 times a
blank (3 to 9) appears on
turn, we
improve to a 82%
favourite. On average we end up collecting $ 35.5 * 36 / 44 = 29.04
4 times we
boat up,
villain will be drawing to 2
outs, PE = 33.89
2 times
villain hit trip Aces. we
fold, and we would have $17.25 - 5.25 = $12 remaining in our
stack.
3 times
villain hit 2-pairs, we fail to get away so we're drawing to 4
outs. PE = 35.5 * 4 / 44 = $3.23
8 times one of the other 2
broadway ranks appear on
turn, giving
villain 12
outs (2
pair or
trips (5) +
gutshot (4) + board
pair (3)). My PE = 35.5 * 32 / 44 = 25.82
Now, (28 * 29.04) + (4 * 33.89) + (2 * 12) + (3 * 3.23) + (8 * 25.82) all divided by 45 = 26.42 (74.4% EV) which is slightly higher than 25.89 (72.9% EV) that we have if we shoved
flop.
In conclusion, the key to this play is my ability to get away from opponent's trip aces. (the 2 * 12 term in my equation). It doesn't make a whole lot of difference in the final PE (just 1.5%), but as I stated before, attention to details like this is probably what turns a winning player into a bigger winner.