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Re: 1 thing i dont get about pot odds
 Originally Posted by defhalotones
Example: Pot holds $100, and costs me $20 to call. I "should" be getting 5:1 odds, but im actually getting 6:1. Shouldnt it be to where im getting 5:1, cuz $20 of the pot will contain my money, which if i win, i will only gain $100. Understand?
To make it easier. You shouldnt count your bet on the pot odds. So why is it still 6:1 on that situation i noted above? Thanks
-Jake-
Your thinking is right. It's not 6:1 in that situation. It's 5:1. You don't count the bet that you're going to have to call as part of the pot because you keep that money if you don't call, meaning that winning it isn't a profit. Ex: Situation you describe above plays out 1000 times. If you win it 16.7% of the time (apx = 5:1), then 167 times you win $120-$20 = gross profit of $16700. 833 times you lose $20 = gross loss of $16660. You got exactly even pot odds and broke even. If, on the other hand, you only won it 14.2% of the time (apx = 6:1), then 142 times you $120-$20 = gross profit of $14200. 858 times you lose $20 = gross loss of $17160. You figured your odds badly and it cost you $3000.
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