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harrington on pot odds

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  1. #1

    Default harrington on pot odds

    i'm currently reading harrington's first tourney installment. in the "reading the table" section, he is outlining a situation and describing an easy call based on pot odds.

    i thought that i understood the fairly straightforward concept, but this confuses me.

    you're holding Qs4s. flop comes JsJc9s. it's going to cost you $200 to get into a $1000 pot. he says that "the odds of drawing a flush on the next card are about 4 to 1 against, and if you stay in for 4th and 5th street, the odds drop to 2 to 1 against."

    i thought that 9 / 47 is roughly 5 to 1 odds against? did dan fuck up, or am i missing something?
  2. #2
    47 cards total. 9 help you, 38 don't. 38 to 9 = 4.2 to 1
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  3. #3
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    Default Re: harrington on pot odds

    Quote Originally Posted by Chrushinator
    he says that "the odds of drawing a flush on the next card are about 4 to 1 against, and if you stay in for 4th and 5th street, the odds drop to 2 to 1 against."
    What he means is that, your odds of hitting solely on the turn are 4:1. The 2:1 odds are you hitting your flush on either the turn or the river.
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  4. #4
    What DaNuts said.

    Probabilities-> good outcomes / (bad outcomes + good outcomes)
    Odds-> bad outcomes : good outcomes

    So if 9 out of 47 cards help you, then you have 9 good outcomes and 38 bad ones. So your odds (of making the flush) is 38:9 and your probability is 9/47. Its just different representations of the same thing.
  5. #5

    Default Re: harrington on pot odds

    Quote Originally Posted by Chrushinator

    i thought that 9 / 47 is roughly 5 to 1 odds against? did dan fuck up, or am i missing something?
    i think you are confusing the chance to make the hand with the odds against making a hand.

    there is a 1 in 5 chance of making the hand by the next card. so every time you play this situation 1 time will make a flush and 4 times will not (total = 1 + 4 = 5).
    this means the odds are 4 to 1 against

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