it was me but that was 7,2 flopping 222 at 19,600 : 1

this situation I think is as follows :

Odds of someone having the same hand as you 271:1 (Heads up this reduces for each player extra) 10 players brings this to 26:1.

Odds of flopping 277 with you and the other dude's holdings.

29,400 : 1

For the whole scenario from start to finish I'm not sure and wouldn't like to guess.

The odds of two people specifically being dealt a pre-determined hand are 48,840 : 1

(4/50)*(3/49)*(4/48)*(3/47) This is for two people, for each player added you would multiply the result, i.e. 10 players result * 9. I'm not sure about this either but its the best i can come up with and I'm sure at best it would only be a rough answer.


I think this is close but I'm not 100%



Please don't flame me for any inaccuraces but please feel free to point out the error of my ways :)