OK who wants to do a calculus problem?

Originally Posted by gabe

what exactly is given (not the answer), and what exactly do you need to show

tan(x/y) = x + y is given

answer in back of book is...

y' = [ysec^2(x/y)-y^2] / [y^2 + xsec^2(x/y)]

10-18-2007 02:26 AM #4
martindcx1e View Profile View Forum Posts Private Message View Blog Entries Join Date Mar 2005 Posts 4,333	Originally Posted by gabe what exactly is given (not the answer), and what exactly do you need to show tan(x/y) = x + y is given answer in back of book is... y' = [ysec^2(x/y)-y^2] / [y^2 + xsec^2(x/y)]
	Wikipedia is the best thing ever. Anyone in the world can write anything they want about any subject. So you know you are getting the best possible information.
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OK who wants to do a calculus problem?

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