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 Originally Posted by chemist
I was thinking effective energy equals mass times some {ongbonga} speed constant squared.
On earth it is acceleration or gravity F=MA, where A is speed squared.
There is nothing special about the Earth in terms of physics. F = ma is true everywhere (everywhere we've looked, at least).
A is acceleration. Acceleration is the derivative of speed with respect to time, or the 2nd derivative of position w.r.t. time.
Acceleration is not speed squared. Dimensional analysis shows the units of acceleration are { L/T^2 }, while the units of speed squared are { L^2/T^2 }.
Furthermore, you're equating force to energy, and they are different things. Energy is (in one form) force applied over a distance.
Kinetic energy is mass times one-half times velocity squared.
Originally Posted by chemist
But why C?
Because Einstein assumed that Energy always travels at the speed of light as a light wave or some other form of radiation.
I can look into this.
Originally Posted by chemist
And Squared because Acceleration is speed squared.
Still no.
Speed is the first derivative of position w.r.t. time.
v = dx/dt
Acceleration is the 2nd derivative of position w.r.t. time.
a = dv/dt = d^2x/dt^2
Jerk is the monkey who points this out twice, while jerk is also the 3rd derivative of position w.r.t. time.
Originally Posted by chemist
Newton F=MA, Einstein E=MC^2
My Universal Equation D=dM*dS^2
Where D is Dimensional Energy, dM is dimensional mass and dS is dimensional speed.
I'm thinking your Universal Equation is suspiciously equivalent to Newton's equation for Kinetic Energy.
Newton KE = M(V^2)/2, Einstein E^2 = M^2 C^4 + P^2 C^2
Part of the beauty of Einstein's equation is that it explains the energy of a massless photon as E = pc while also describing the intrinsic mass of a stationary (resting) particle as E = mc^2. It also predicted the change in mass associated with temperature change.
EDIT: I can't believe I forgot the factor of (1/2) in the Kinetic Energy.
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