Why are two card odds only applicable when going all in?

I've been reading an article on odds which gives odds of completing the draw on the turn and river.

e.g. set to a full house. 7 outs. 5.6:1 to complete on turn, 2.6:1 to complete on turn or river.

BUT the article says you can only use the 'turn or river' odds if you are going all in on the hand.

Why is this?

Thanks.

because if you're not all-in before the turn, then you may not even see the river. You should thus make your decision on pot odds, with another similar decision to make on the turn. If you're going all-in on the flop, then you're guaranteed to see both cards - does that make sense?

also, it's set -> full house or quads to make 7 outs on the turn, you then have 10 outs on the river.

Thanks I understand now why you can only use those odds if going all in (combined odds) that's great.

Set to full house. You have three cards the same so you have two left, either of which needs to be paired. There are 4 cards of the same type in each deck, so you have 6 outs, plus the one other card to make your quad - so 7 outs, on the turn. I think I've got that right thanks, why do you get an extra three outs on the river?

Originally Posted by daven

because if you're not all-in before the turn, then you may not even see the river. You should thus make your decision on pot odds, with another similar decision to make on the turn. If you're going all-in on the flop, then you're guaranteed to see both cards - does that make sense?

also, it's set -> full house or quads to make 7 outs on the turn, you then have 10 outs on the river.

This. If you call all-in on the flop you are certain that is the odds you are getting, as you won't have to call another bet on the turn. But if you are getting 2:1 on the flop to see if you get your flush draw (~2:1 to complete if you get to see both cards), and you anticipate he will bet again on the turn, you aren't getting the correct pot odds. Because you only get to see one card for the price you are paying, and the chances of hitting 9 outs on one card is 4:1.

Note: this doesn't include implied odds.

Originally Posted by LuckySlevin

Set to full house. You have three cards the same so you have two left, either of which needs to be paired. There are 4 cards of the same type in each deck, so you have 6 outs, plus the one other card to make your quad - so 7 outs, on the turn. I think I've got that right thanks, why do you get an extra three outs on the river?

The river can pair whatever comes on the turn.

of i see of course, thanks