Uh Zenbitz, you're wrong - K9872 splits because both K6 and K3 have a final hand of KK987.
08-30-2006 12:08 PM
#6
| |
![]() ![]()
|
Uh Zenbitz, you're wrong - K9872 splits because both K6 and K3 have a final hand of KK987. |