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Let's make this more specific: say the second Villain has 5c4s and also has a $5 stack. We make our $5 bet, and assume Villain 1 acts first while Villain 2 acts second.
From highest EV to lowest EV:
$12.00 - Both fold
$10.93 - AhKh calls, 5c4s folds
$10.09 - AhKh folds, 5c4s calls
$7.23 - Both call
Here the fundamental theorem holds since we benefit by their mistakes no matter what happens. Can you come up with hands for the two Villains here where the fundamental theorem doesn't hold?
Math Shit Below Showing The EV Of Each Possible Outcome
If both call:
Code:
Board: 7d 6c 2h
Dead:
equity win tie pots won pots tied
Hand 0: 45.293% 45.29% 00.00% 409 0.00 { 9h9s }
Hand 1: 23.588% 23.59% 00.00% 213 0.00 { AhKh }
Hand 2: 31.118% 31.12% 00.00% 281 0.00 { 5c4s }
Our EV is (0.45293)(12+5+5) + (1-0.45293)(-5) = $7.23.
If AhKh calls and 5c4s folds:
Code:
Board: 7d 6c 2h
Dead:
equity win tie pots won pots tied
Hand 0: 72.424% 72.42% 00.00% 717 0.00 { 9h9s }
Hand 1: 27.576% 27.58% 00.00% 273 0.00 { AhKh }
Our EV is (0.72424)(12+5) + (1-0.72424)(-5) = $10.93.
If AhKh folds and 5c4s calls:
Code:
Board: 7d 6c 2h
Dead:
equity win tie pots won pots tied
Hand 0: 68.586% 68.59% 00.00% 679 0.00 { 9h9s }
Hand 1: 31.414% 31.41% 00.00% 311 0.00 { 5c4s }
Our EV is (0.68586)(12+5) + (1-0.68586)(-5) = $10.09.
If both fold, our EV is $12 since we just win the pot.
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