Quote Originally Posted by jackvance
12/50*8/49*4/48*4=1.306%
To extend, what Jack here did was looked at the odds of hitting one type of straight, let's say the idiot end. In order to get that, you need the flop to be 9TJ. The first card delt needs to be any one of those - 12 possibilities from 50. The next card needs to be one of the two remaining non-representing ranks, 8 possibilities from 49. The last must be the remaining non-represented rank, so 4 possibilities from 48. The chance of all three happening is the product of those individual probabilities, so the chance of hitting one type of straight is 12/50 * 8/49 * 4/48. There's 4 types of straights given 78 hole, so multiply by 4 and you've got your answer - 1.306%.