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Re: pot odds question
Ok, after reading Koolmoe's and mike007's posts about 10 times, I think I understand. I hope I'm not going to make a fool of myself so here goes..
Basically, the problem with the original post is the figure of 24.33 is calculated incorrectly.
When caluclating pot odds, the "pot size" is considered to be all the money that will be in the pot after you call the bet. It turns out that if the pot is currently $100, the max bet that your opponent could make that you could call would be about $32, not $24.33. I just figured that out through trial and error. If the pot was $100, and one person bet $32 and you call, then the total "pot size" is $164.
(.1957)*$164 = $32.
So in your EV equation, if we put in the values of $32 (the amount you would lose about 80% of the time) and $132 (the amount you would win about 20% of the time), it works out.
EV = 0.1957*(132) + (1-0.1957)*(-32) = about 0
So.. if I'm understanding this correctly... Tyson's pot odds essay is wrong? He doesn't include his own call as a part of the total pot size. Is this what you're saying koomoe?
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