I think I actually did this calcuation, or a similar one in another thread:

if you hold AQ, chance of the the next guy holding AK = 3 *4 / 50 * 49 = .005. The chance of NO ONE holding AK = .995^9th power

~96%

Now, that doesn't count the other hands that kick your ass - AA/KK/QQ - there are 6+12+6 = 24 more of those, so it would b a 12.7% chance (about 1 in 8) that someone dominates you.