BigSlikk,

You're right, your way is confusing and turns simple equasions into long winded ones

The most common way of calculating odds that I have seen is the manner as I illustrated and, most importantly, it is the same way that Gordon uses once he has number of outs.

Remember, the article contains his methodology and then the quiz to showcase how it works. So, if using Gordon's own method indicates that $282 is too low then how did he reach it?

I like to think of pot odds as thus: A flush draw comes once every three times
With one card to come, the odds of making the flush are not 1/3 . However you do it, be it 9/44 or (9 x 2) +1, his odds should still be as indicated above: 1 in 5.5 - which is 4.5: 1 - which is 18%.


which includes the last street's pot, plus your opponent's bet, and your eventual call
There is no bet to call. Your opponent has not made any bet.


working it out on paper before reading any responses.....all I need to do is use the rule of two / rule of four to get percentages.
It is not my intention to be rude but if you had read my responses you would see that said rule has already been implemented, as well as breaking down why it shows that $282 doesn't fit.

As a side issue, If you use the rule of 2 and 4 to get your percentage I can't see why you overcomplicate the process. Simply convert that percentage into your preferred ratio format.