Basic Bankroll Management Math: An Instructive Example

Originally Posted by daviddem

It is the same. The EV for each roll is 47.2, so total EV for both rolls = 94.4.

There is a typo in Spoon's post though where he writes 94,444,444= approximately 95.5 (instead of 94.5, or 94.4)

Note also that in the first scenario, you either win 100mils or loose it all, whereas in the second scenario, you also have a chance to break even (and as a consequence, you also have less chance to win 100mils than you do in the first scenario):
Chance to loose it all: 1/36*1/36=1/1296=0.08%
Chance to win it all: 35/36*35/36=94.52%
Chance to break even: 100-94.52-0.08=5.4%

Whereas in the first scenario your chance to win 100mils is 35/36=97.2%

I caught the typo, that's not what I meant. I was wondering what is the negative effect spoon refers to in this sentence:

Originally Posted by spoonitnow

By doubling the number of buy-ins we use for our bankroll management in this dice game, we've cut our expected value in half for each roll which has a negative effect, but we've cut our risk of ruin down by a much higher factor.

You're saying that the negative effect is less chance to double up even though the overall EV is the same?