semi-bluff maths help pretty please
ok so i'm reviewing some hands and one came up where i thought this piece of knowledge, and specifically how to acquire it, would be very helpful for me.
basically i want to know how to determine the required amount of pot equity for all in semi-bluffs to be neutral EV based on certain amounts of fold equity. for the sake of discussion, here's the hand and risk/reward amounts simplified.
PokerStars No-Limit Hold'em, $0.10 BB (5 handed) - PokerStars Converter Tool from FlopTurnRiver.com
UTG ($20.38)
MP ($10.10)
Button ($10)
Hero (SB) ($14.52)
BB ($9.25)
Preflop: Hero is SB with two cards.
2 folds, Button bets $0.30, Hero raises to $1.05, 1 fold, Button calls $0.75
Flop: ($2.20) 8:club:, 5:club:, 4:spade: (2 players)
Hero bets $1.20, Button raises to $3.45, Hero raises to $13.47 (All-In), Button calls $5.50 (All-In)
pot at point of hero's shove: $2.2 + $1.2 + $3.45 = $6.85
hero's risk is $7.75 (how much villain has left in stack + how much he raised me by)
is there some equation we can set up to determine what the minimum amount of equity i need for a shove to be neutral EV if villain folds x% of the time? for posterity, let's say i estimate my opponent will fold 10% of the time. what is the easiest way to determine the exact amount of pot equity i need for a shove to be 0EV (and hence, the bottom of my shoving range)
thankyou for any responses.