very basic questions about implied odds for NL

I’m a newbie Fixed Limit player just starting to play NL and am trying to figure out how implied work in NL. Here’s a fairly basic questions about what to do assuming we’re playing a very straightforward game....


Let’s say I have an open-ended nut straight draw on the turn; with 8 outs I’m about a 5:1 dog to make it by the river. The pot is currently $2 and my calling station opponent, who I’m convinced has top pair, puts in a $1 bet making the pot odds 3:1. (In fixed limit this would be an easy fold since the bet amounts on fourth & fifth street don’t change, but I think not necessarily so in NL.) Let’s say I pretty “sure” he would call a larger bet from me on the river if I make my straight.


So the question: what would be the minimum amount I’d have to expect to get from him (assuming he’ll call me) on the next street? Or another way to put it: in order to calculate implied odds for calling, bet how much theoretically would I need to think of being in the pot now? ... $5? ($3 to call now plus at least $2 on the river.)



Wouldn't the math be something like this: Drawing odds (in this case 5:1) minus pot odds (currently 3:1) = implied odds (2:1)? Arrrg.

its the same thought process

2$ in pot, he bets 1$ so you call 1$ to win 3$, (3:1) so you need to average >2$ on the river for the call to be profitable. what you said is basically right, just think through the logic instead of making an equation and it will make your head spin less lol

He's betting $1, you want 5:1, that means you want to win $5 total, you're getting $3 of that immediately from the pot, so you want another $2 on average on the river to break even. Pretty ez.