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Maths prob
My bad maths...
I play Whist at work, but am struggling with a very basic maths prob!!! I've tried google, but can't find anything and my head is spinning.
General idea on the last round of the game:
each player gets dealt 1 card, then the top of the pack is turned up as the Trump, then each player "bids" in turn. But the bids can't add up to the cards dealt (1). Eg: player A bids 1, player B bids 0, player C has to bid 1.
On this particular game, there were 3 players.
Player A gets dealt the 4h.The trump is 10d (so diamonds).
So should player A bid 1 with 2 players behind him?
Cards that beat him: 12d's, 10h's = 22 cards
Cards that can't beat him : 13c's, 13s's, 3h's = 29 cards.
The answer is probably yes on this occasion, but how does the probablity change as the players increase? Anyone give me the formula???
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I don't understand the bidding system, but the chances that he's beat are 1-[1-22/(50-n)]^n where n is the # of players
amirite?
In your deck there are 14 hearts... but idk if the A is high or low, so I left it.
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thanks.
soemone else answered on another post, and I refined it a bit
1- ((28/50)*((28/49))
so infact I shouldn't bid 1 and should bid 0, as theres a 68% chance someone will have a Trump card or a higher heart (than my 4h).
It's really good game Whist for playing for no money.
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