Help with Programming/Maths!

Ok... here's an iterative formula which works in my program

Code:

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for i = 0 to t
  B=B+xy(a^i)
next

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basically I am trying to work out B.

I KNOW x, y and a... they're constants. It's fairly simple when you replace them with numbers.

It's the same as saying

Code:

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B = xy(a^0) + xy(a^1) + xy(a^2)... and so on

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What i need to do is write a similar loop or function or whatever which allows me to calculate x, assuming i know B.

It might be something like

Code:

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x = b/y + b/ya ...

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Do you see what I mean? I can't figure it out! this is for that bankroll calculator, by the way!

I am 27. I last did this shit when i was 21. That is a long time

If anyone knows what a for..next loop is and can do algebra/math but doesnt understand the question then please post because i might be able to explain it better

ugh my head hurts gg you pwned me

lol

its not that difficult. someone who has done a maths or science degree (and wasn't continually stoned for all 3 years like I was) will eat it for lunch

i'm hoping for demiparadigm or someone

well I havent done a degree in that and I hate math IM so pwned :(

unless i didn't misunderstand, that would mean that:

B=xy [ (a^0) + (a^1) + (a^2) + ... + (a^t) ]

Thus,

1/x = y/b [ (a^0) + (a^1) + (a^2) + ... + (a^t) ]



=> x = b/y [ (a^0) + (a^1) + (a^2) + ... + (a^t) ]

=> FOR 0<=i<=t x = b/y (SUM** a^i)


** Sum -> think excel sum formula...I'm sure you can handle that in programming.

B=B+xy(a^i)

B=xya + xya^2 + xya^3 + xya^t
B=xy(a + a^2 + a^3 + a^t)
B/y(a + a^2 + a^3 + a^t) = x

so the code is:

for i = 0 to t
C=C+(a^t)
next
x=B/(yC)


am i close?

Whoa some serious responses. Thanks. They're very similar to my attempts but subtly different... going to give them a go...

To explain all the variables...

x = table buyin e.g 25 for $25NL
y = "caution factor" e.g. 20, if you want 20 * buyins for your bankroll
B = bankroll
t = number of tables you're playing...
a = multi tabling factor... the lower this is the less effect multitabling has on bankroll requirements.

If you are 3 tabling 25NL with a standard "caution factor" of 20... and we call the a factor 0.25(Thru trial and error I think this is reasonable)
then i work out that your required bankroll B is....

B = (25 * 20 * 1) + (25 * 20 *0.25) + (25 * 20 * 0.0625)
B = 656.25

So if i plug in 656.25 into the other formula, then x should come out at 25, AMIRITE?

gabe yours says...
C = 0.25^0 + 0.25^1 + 0.25^2 = 1.3125
x = 656.25/(20 * 1.3125)
x = 25

B.I.N.G.O!!!!

Hate, thanks for the help but I didn't really understand the SUM bit!!! Looks v similar though.

Thanks very much. New BR calculator will have mad props to you for the help...

I'm not sure what language you're programming, but my SUM is the equivalent of the excel SIGMA formula ( http://images.google.com/images?q=tb...lhwd/sigma.gif )