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# NLHE Foundations Course #01: Exercises

1. ## NLHE Foundations Course #01: Exercises

Last edited by spoonitnow; 06-17-2015 at 05:26 PM.
2.  06-17-2015 05:49 PM relaywisp Join Date Jun 2015 Posts 15 You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76. AK - 4 * 3 = 12 AQ - 4 * 4 - 16 AA - 6 KK - 3 A8 - 4 * 2 = 8 76 - 3 * 4 = 12 AK(12), AQ(16), AA(6), KK(3), A8(8), 76(12)
3.  06-17-2015 06:31 PM MarinaD Join Date Jun 2015 Posts 35 AK(12), AQ(16), AA(6), KK(3), A8(8), 76(12).
4.  06-18-2015 03:35 AM MrFerguson91 Join Date Nov 2014 Posts 206 Location Belfast NI My Answers You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76. AK(12) AQ(16) AA(6) KK(3) A8(8) 76(12) I had to do this a few times before getting the right answers it seems pretty complicated at first to remember all the calcuations, although I am going to do it a few more times could I have another example or two to work through today and I can PM you my answers I find it off putting seeing the answers in this thread
6.  06-18-2015 09:37 AM MrFerguson91 Join Date Nov 2014 Posts 206 Location Belfast NI Cheers man I get it now seems really simple once it clicks into your brain, I'll practice more tonight while playing my MTTS and SNGs to get it to sink in even further, this is to basically narrow down ranges and to give a bit more of an insight into what villain might possibly be holding is that correct?
7.  06-18-2015 11:43 AM spoonitnow Resident Asshole Join Date Sep 2005 Posts 14,499 Location North Carolina Well the idea is that it's more likely for someone to have some hands than others just based on which cards have been dealt. If we have AA on QT4 then it's easier for our opponent to have KK(6) than QQ(3), for example. Soon we're going to use this idea to do some fun stuff like decide if certain bluffs are profitable.
8.  06-18-2015 10:17 PM MarinaD Join Date Jun 2015 Posts 35 I'm doing 10-15 min drills per day of this exercises. It's not difficult, but i want to be really fast doing this. Didn't explain my results because it's a very automatic process, but i'll do it next time. Looking forward to the next lesson. Really hope to be soon. Thanks and sorry for my english Last edited by MarinaD; 06-18-2015 at 10:23 PM.
9.  06-19-2015 03:25 AM MrFerguson91 Join Date Nov 2014 Posts 206 Location Belfast NI Cool no probs Looking forward to the next part Last edited by MrFerguson91; 06-19-2015 at 11:59 AM.
10.  06-19-2015 07:43 AM 1QDOG7 Join Date May 2015 Posts 4 Thanks Spoon. I have always struggled counting combos so this is really useful. Are there any similar methods for quickly counting the different ways that an opponent could have 2 cards of a particular suit in the case of flush draws? The best I've come up with is: Using spades for the example ((13-#of spades on board)*((13-#of spades on board)-1))/2 Not quite as easy to swallow!
11.  06-19-2015 08:38 AM spoonitnow Resident Asshole Join Date Sep 2005 Posts 14,499 Location North Carolina Originally Posted by 1QDOG7 Thanks Spoon. I have always struggled counting combos so this is really useful. Are there any similar methods for quickly counting the different ways that an opponent could have 2 cards of a particular suit in the case of flush draws? The best I've come up with is: Using spades for the example ((13-#of spades on board)*((13-#of spades on board)-1))/2 Not quite as easy to swallow! Hey! We're going to get into that soon. It's easier to actually just count out the different hands that our opponent could have based on his play than trying to think about every single possible combination of cards that would give the guy a flush or flush draw.
12.  06-19-2015 06:14 PM Turbo4life Join Date May 2015 Posts 10 ou hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76. AK - 4 aces x 3 Kings, 12 AQ - 4 aces x 4 Queens , 16 AA, 4 aces ... 6 ways using the 6310 rule KK - 3 ways using the 6310 rule A8 - 4 aces x 2 8s, 8 76 - 3 7s x 4 6s, 12
13.  06-20-2015 01:57 AM MadMojoMonkey AINT SHOVELING SHIT Join Date Apr 2012 Posts 9,149 Location St Louis, MO I'm completely distracted by the fact that when spoony quoted the '#' it became a != sign. Show me how to use this magic! (This course is amazing and I'm following along.)
14.  06-20-2015 02:06 AM spoonitnow Resident Asshole Join Date Sep 2005 Posts 14,499 Location North Carolina Originally Posted by MadMojoMonkey I'm completely distracted by the fact that when spoony quoted the '#' it became a != sign. Show me how to use this magic! (This course is amazing and I'm following along.) I don't see what you're talking about and/or it didn't do it for me. PM me a screenshot?
15.  06-20-2015 04:48 PM matiusaa Join Date Dec 2013 Posts 113 Hi, sorry I arrived late at class, but I will do the excersice anyways: We hold 7s8s and the board is Ks8h5s: AK(12): there's one K so there are 4 A in the deck and 3 K in the deck so 4*3=12 AQ(16): there are four A and four Q in the deck so 4*4=16 AA(6): there are 4 A in the deck so there are 6 combinations (6310 rule) KK(3): there are 3 K in the deck so there are 3 combinations (6310 rule) A8(8): there are four A in the deck and two 8 so 4*2=8 67(12): there are four 6 in the deck and three 7 so 4*3=12 Last edited by matiusaa; 06-20-2015 at 04:51 PM.
16.  06-20-2015 04:57 PM matiusaa Join Date Dec 2013 Posts 113 I had no problem doing the excersices, and I find it really easy doing the math in my head quickly. How can we put this into practice at the tables? Should we do this after we range our opponents and do a qualitative equity, or there's a math process to calculate our equity?
17.  06-24-2015 05:06 PM Kashkar Join Date Jun 2015 Posts 9 You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76. AK(12) AQ(16) AA(6) KK(3) A8(8) 76(12) I know I'm late to the game and answers are already posted, but I figured I'd take part anyways lol.
18.  06-24-2015 06:46 PM spoonitnow Resident Asshole Join Date Sep 2005 Posts 14,499 Location North Carolina Originally Posted by matiusaa I had no problem doing the excersices, and I find it really easy doing the math in my head quickly. How can we put this into practice at the tables? Should we do this after we range our opponents and do a qualitative equity, or there's a math process to calculate our equity? Hey I just want to point out that you shouldn't be trying to count combinations out for a range like this at the table. I tried to reference that in the actual lesson, but I just want to reiterate that here. However, we are going to use this as a tool during our study, and I'm going to show you how to study in a way that will give you a much better feel for poker. That's actually one of the major skills I want to give you for this course because so many people aimlessly study random topics without having a system in place for getting better and making more money. Originally Posted by Kashkar You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76. AK(12) AQ(16) AA(6) KK(3) A8(8) 76(12) I know I'm late to the game and answers are already posted, but I figured I'd take part anyways lol. Hey there's not really a time limit on this or anything, so don't feel like you're super behind or something. Feel free to just complete them at your own pace. I'm estimating that there will be 8-10 of these lessons for this initial course, and I'm going to do more stuff after that on different topics.
19.  07-05-2015 10:04 AM bhaley66 Join Date Sep 2009 Posts 179 Location CA You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76. AK(12) - Four Aces, & Three Kings left in the deck - 3*4=12 AQ(16) - Four Aces, & Four Queens left in the deck - 4*4=16 AA(6) - 6310, No Aces blocked - 6 KK(3) - 6310, One King blocker - 3 A8(8) - Four Aces, & Two Eights left in the deck - 4*2=8 76(12) - Three Sevens, & Four Sixes left in the deck - 3*4=12
20.  07-07-2015 01:47 AM JoeHaw Join Date Mar 2009 Posts 252 Location IL You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76. AK(12), AQ(16), AA(6), KK(3), A8(8), 76(12) Nothing new to contribute here just moving along :P I'm a great believer in luck, and I find the harder I work the more I have of it. -Thomas Jefferson Opportunity is missed by most people because it is dressed in overalls and looks like work. -Thomas Edison
21.  07-27-2015 04:50 AM Pursu7it Join Date Jul 2015 Posts 23 You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76. 1.) 4*3 = 12 AK(12) 2.) 4*4 = 16 AQ(16) 3.) AA(6) because of the 6310 shortcut 4.) KK(3) because of the 6310 shortcut 5.) 4*2 = 8 A8(8) 6.) 3*4 = 12 76(12)
22.  07-31-2015 03:12 PM Blue Chip Join Date Jul 2015 Posts 18 Location Montville, NJ You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76 AK =12 (4x3) AQ =16 (4x4) AA =6 (6310 rule, nothing on board) KK =3 (6310 rule, 1 on board) A8 =8 (4x2) 76 = 12 (3x4)
23.  07-31-2015 11:17 PM spoonitnow Resident Asshole Join Date Sep 2005 Posts 14,499 Location North Carolina Hey guys, these answers look good. Keep up the good work.
24. ## Exercise #1

You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76.

AK(12) 4-A left x 3-K left in the deck
AQ(16) 4-A left x 4-Q left in the deck
AA(6) using 6310 method no A showing leaving 6 combos
KK(3) using the 6310 method 1 K is showing leaving 3 combos
A8(8) 4-A left x 2-8 left in the deck
76(12) 3-7 left x 4-6 left in the deck
25.  08-11-2015 10:43 AM Cobra_1878 Join Date Jul 2012 Posts 1,384 Location Liverpool You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76. AK - 4 As and 3 Ks (4*3) = 12 combos. AQ - 4 As and 4 Qs (4*4) = 16 combos. AA - Using 6310 = 6 combos of AA. KK - Using 6310 = 3 combos of KK. A8 - 4 As and 2 8s (4*2) = 8 combos. 76 - 3 7s and 4 6s (3*4) = 12 combos. Currently grinding live cash games. Life is good.
26.  08-13-2015 01:31 PM spoonitnow Resident Asshole Join Date Sep 2005 Posts 14,499 Location North Carolina Originally Posted by Rambam77 You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76. AK(12) 4-A left x 3-K left in the deck AQ(16) 4-A left x 4-Q left in the deck AA(6) using 6310 method no A showing leaving 6 combos KK(3) using the 6310 method 1 K is showing leaving 3 combos A8(8) 4-A left x 2-8 left in the deck 76(12) 3-7 left x 4-6 left in the deck Originally Posted by Cobra_1878 You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK, AQ, AA, KK, A8, 76. AK - 4 As and 3 Ks (4*3) = 12 combos. AQ - 4 As and 4 Qs (4*4) = 16 combos. AA - Using 6310 = 6 combos of AA. KK - Using 6310 = 3 combos of KK. A8 - 4 As and 2 8s (4*2) = 8 combos. 76 - 3 7s and 4 6s (3*4) = 12 combos. Good job guys. I know that this is something that some people have seen before, but it's pretty critical to be able to do this, and that's why I've included it as the first lesson.
27.  08-30-2015 10:54 PM othd13 Join Date Aug 2015 Posts 11 AK:12 AQ:16 AA:6 KK:3 A8:8 76:12 Last edited by othd13; 08-30-2015 at 10:55 PM. Reason: wrong
28.  08-30-2015 11:15 PM spoonitnow Resident Asshole Join Date Sep 2005 Posts 14,499 Location North Carolina Originally Posted by othd13 AK:12 AQ:16 AA:6 KK:3 A8:8 76:12 Hey if you think you've got this, then that's awesome. If you don't, then let me know in this thread.
29.  08-31-2015 08:08 AM othd13 Join Date Aug 2015 Posts 11 yeah, i think i got this, hope you check my exercises on course 2 soon. Very thank you soonoitnow!
30.  09-03-2015 08:38 AM siriusisness Join Date Nov 2014 Posts 13 AK: 12 AQ: 16 AA: 6 KK: 3 A8: 8 76: 12 looking over everyone elses answers - looks like i got them right weeeeee - its like being at school again also thanks for all the effort youve put into this mate, i really appreciate it Last edited by siriusisness; 09-03-2015 at 08:40 AM. Reason: to say thanks
31.  09-03-2015 04:28 PM spoonitnow Resident Asshole Join Date Sep 2005 Posts 14,499 Location North Carolina Originally Posted by siriusisness AK: 12 AQ: 16 AA: 6 KK: 3 A8: 8 76: 12 looking over everyone elses answers - looks like i got them right weeeeee - its like being at school again also thanks for all the effort youve put into this mate, i really appreciate it No problem. I hope you enjoy it and make it through all of the parts of the course that are up.
32.  09-16-2015 11:26 PM Robb Join Date Aug 2007 Posts 3,275 You hold 8s7s on a board of Ks8h5s. Find the number of starting hand combinations for the following hands: AK(12), AQ(16), AA(6), KK(3), A8(8), 76(12).
33.  09-18-2015 09:43 AM BorisTheSpider Join Date Mar 2012 Posts 861 Location UK AK(12), AQ(16), AA(6), KK(3), A8(8), 76(12)
34.  09-23-2015 12:27 PM doddly10 Join Date Aug 2015 Posts 17 AK(12) AQ(16) AA(6) KK(3) A8(8) 76(12) off to #2
35.  09-24-2015 10:13 PM spoonitnow Resident Asshole Join Date Sep 2005 Posts 14,499 Location North Carolina Good stuff guys. I know that this lesson seems kind of straight-forward and maybe even trivial because of how relatively simple it is, but it's something that you really need to be able to do some pretty incredible analysis that we'll get into.
36.  09-28-2015 05:52 AM ErnieohneBert Join Date Sep 2015 Posts 23 Location Munich 8s7s on a board of Ks8h5s. AK = 12 AQ = 16 AA = 6 KK = 3 A8 = 8 76 = 12

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