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Math Behind Crown and Anchor Game

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  1. #1

    Default Math Behind Crown and Anchor Game

    (Mods, If this post is better suited for the commune please feel free to move, wasn't sure where to post this)

    So I just came from my buddie's Jack and Jill (or Stag and Doe or whatever) and they had a pretty common game there called Crown and Anchor. For those unfamiliar: http://en.wikipedia.org/wiki/Crown_and_Anchor

    We played with a spinning wheel though, not dice. The wheel looks like this:




    The game is simple, people can play a minimum of $1 to a maximum of $5 per turn (at least that's what we did) You then spin the wheel and payouts are determined by how many symbols are on the winning spin:

    1 symbol pays 1:1
    2 symbols pay 2:1
    3 symbols pay 3:1


    First, I was just trying to derive the house edge for this game, but since I was drinking a bit (yes I was trying to do this AT the party) I came up with this:

    there are 12 winning spins with 3 identical symbols
    there are 12 winning spins with 2 identical symbols and 1 differing symbol
    there are 4 winning spins that have no identical symbols
    there are 28 total options for a winning spin

    Then I imagined to come up with the house edge for the game, I pretended what would happen if I were to bet $1 on every symbol (yes I realize I said the house max was 5$, but just go with it)

    based on this, I came up with the expectation of that play to be:

    (12/28)(4)+(12/28)(5)+(4/28)(6)= $4.70

    so whenever we bet $1 on each symbol, our expectation is $4.70. but this is not the house edge that I found when I googled it (house edge = 7.5% apparently)

    This leads me to believe that there is a way to bet this game optimally, but I do not know how to find that out.

    Please help me figure this out, and let me know if any of my math/assumptions are wrong.


    Thanks!


    Caddie444


    Don't complain; Just work harder - Randy Pausch (The Last Lecture)
  2. #2
    its a crap shoot really just a fun game can't beat the house EVER in a game like this lol
  3. #3
    When I look at this and see that they pay 3:1 on every spin and there are 6 symbols, how are they not getting 50%? Then upon counting you get paid 12x on the wheel of 28 spaces and it seems even more so.
  4. #4
    Quote Originally Posted by steelsatin View Post
    its a crap shoot really just a fun game can't beat the house EVER in a game like this lol
    That's insulting to crap shoots. As I remember playing the pass line and laying 3 times (free) odds meant the house edge was only about 0.5%.
    Last edited by Monster Agent Zero; 06-24-2013 at 04:34 PM.

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