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Demiparadigm
Old 09-21-2005, 01:48 AM     Post subject: A math problem: #1 (permalink)  
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3 men are travelling, and find a hotel to spend the night.
They are told it will be $30 for the three of them to share a room.
They each pay $10, and go to their room.
Later, the Hotel Manager realizes that he had overcharged them, and a room is only $25.
He gives the bell boy $5 to return to the 3 men.
The bell boy realizes that the men can not split $5 evenly so he decides to keep $2 for himself and give each of the men $1.

So now, each man paid $9 for a total of $27, and the bell boy kept $2, for a total of $29.

Where did the last dollar go?
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daluchy
Old 09-21-2005, 01:55 AM #2 (permalink)  
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Well if a room is $25, 25/3 =$8.333

So the kid gives each one back a dollar from their $10
$8.333 + $1 = $9.333

So their money back plus what the kid took
$9.333 * 3 + $2 = $30
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kc8986
Old 09-21-2005, 01:56 AM     Post subject: Re: A math problem: #3 (permalink)  
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Quote:
Originally Posted by Demiparadigm
3 men are travelling, and find a hotel to spend the night.
They are told it will be $30 for the three of them to share a room.
They each pay $10, and go to their room.
Later, the Hotel Manager realizes that he had overcharged them, and a room is only $25.
He gives the bell boy $5 to return to the 3 men.
The bell boy realizes that the men can not split $5 evenly so he decides to keep $2 for himself and give each of the men $1.

So now, each man paid $9 for a total of $27, and the bell boy kept $2, for a total of $29.

Where did the last dollar go?
Nice little bit of mis-direction

$25 (in the register) plus $2 (in bellboy's pocket) = $27 (paid by the 3 men)
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Tim Vecchioni
Old 09-21-2005, 07:01 PM #4 (permalink)  
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im still confused out of my mind....screw the 8.333 you dont give back 8.333 you give back whole numbers...lets see they all pay 10 to equal 30...guy takes 5 out...gives each one 1 and keeps 2... ahhhh the misdirection is when you say they all payed 9...when in theory they didnt... because they shoulda got more then $1 back...wooo! i figured it out.

-10 + 1 * 3 = 27 however this isnt the true equation for what they payed... this is after the fucking bell hopper bitch SCREWED THEM!!!
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a500lbgorilla
Old 09-21-2005, 07:05 PM     Post subject: Re: A math problem: #5 (permalink)  
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Quote:
Originally Posted by Demiparadigm
3 men are travelling, and find a hotel to spend the night.
They are told it will be $30 for the three of them to share a room.
They each pay $10, and go to their room.
Later, the Hotel Manager realizes that he had overcharged them, and a room is only $25.
He gives the bell boy $5 to return to the 3 men.
The bell boy realizes that the men can not split $5 evenly so he decides to keep $2 for himself and give each of the men $1.

So now, each man paid $9 for a total of $27, and the bell boy kept $2, for a total of $29.

Where did the last dollar go?
ALL MATH HAS BROKEN DOWN! I will turn this in instead of my completed Diff Eq test and tell my teacher that all math in the universe is wrong.

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You mean the revolver, sir?
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PokerPatNEU
Old 09-21-2005, 07:13 PM #6 (permalink)  
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Differential Equations was the most ridiculous math class i've ever taken. LaPlace Transforms!? Wtf, come on...Applications prz? thx ^.^
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chardrian
Old 09-21-2005, 07:46 PM     Post subject: Re: A math problem: #7 (permalink)  
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Quote:
Originally Posted by Demiparadigm
3 men are travelling, and find a hotel to spend the night.
They are told it will be $30 for the three of them to share a room.
They each pay $10, and go to their room.
Later, the Hotel Manager realizes that he had overcharged them, and a room is only $25.
He gives the bell boy $5 to return to the 3 men.
The bell boy realizes that the men can not split $5 evenly so he decides to keep $2 for himself and give each of the men $1.

So now, each man paid $9 for a total of $27, and the bell boy kept $2, for a total of $29.

Where did the last dollar go?
Are you a 5th grade math teacher? 5th grade is when I first heard this problem. $25 in register + $2 in bellboys pocket = $27
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Tim Vecchioni
Old 09-21-2005, 07:53 PM     Post subject: Re: A math problem: #8 (permalink)  
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Quote:
Originally Posted by chardrian
Quote:
Originally Posted by Demiparadigm
3 men are travelling, and find a hotel to spend the night.
They are told it will be $30 for the three of them to share a room.
They each pay $10, and go to their room.
Later, the Hotel Manager realizes that he had overcharged them, and a room is only $25.
He gives the bell boy $5 to return to the 3 men.
The bell boy realizes that the men can not split $5 evenly so he decides to keep $2 for himself and give each of the men $1.

So now, each man paid $9 for a total of $27, and the bell boy kept $2, for a total of $29.

Where did the last dollar go?
Are you a 5th grade math teacher? 5th grade is when I first heard this problem. $25 in register + $2 in bellboys pocket = $27
yes it easy but when you read the

"So now, each man paid $9 for a total of $27, and the bell boy kept $2, for a total of $29."

it throws you off, thats the whole point im pretty sure of this problem.
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chardrian
Old 09-21-2005, 08:09 PM #9 (permalink)  
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I just re-read my post and realized that I sounded like a complete ass. Even worse was the fact that I didn't even realize I copied someone else's response. Didn't mean to - sorry. I honestly heard this problem when I was in fifth grade - it was extra credit at the end of some test. I got a Snickers for answering it correctly.

Although the math might be easy - it still screws with all the logic that you have. That's why I love problems like these. It's very similar to the Let's Make a Deal 3 doors problem where logically it makes sense that whether or not you change your door makes no difference, but really you have a 2/3 shot by changing and only 1/3 by keeping your original choice.
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Old 09-21-2005, 09:21 PM #10 (permalink)  
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you just blew my mind
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CrunchyNuts
Old 09-21-2005, 10:52 PM #11 (permalink)  
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Quote:
Originally Posted by PokerPatNEU
Differential Equations was the most ridiculous math class i've ever taken. LaPlace Transforms!? Wtf, come on...Applications prz? thx ^.^
You had a really bad DiffEq prof if you don't know the applications of that stuff. As for mine, he was fixated on motion in a dampening field. Specifically, a field of peanut butter. Mmm, peanut butter.
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Demiparadigm
Old 09-22-2005, 01:40 AM #12 (permalink)  
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I didn't say it was a HARD problem.
If you feel I have insulted your intelligence try this one:

If you have 5000gallons of water(closed system) in an ammonia equilibrium with a pH of 10 and 20ppm H2 as an Oxygen scavenger,
How many litres of air must be added to lower pH to 9?

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