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HiLo
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01-19-2008, 07:53 PM
Post subject: Algebra / Probability Genius Required
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#1 (permalink)
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Flush
Join Date: May 2007
Posts: 250
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Can one of you maths geniuses help me solve this problem:
I am being offered decimal odds on 4 possible outcomes of a race @
1.79, 5.48, 9.35 & 6.35
I can work out the implied probabilities from these odds as follows:
runner A: 1.79 = 55.86%
runner B: 5.48 = 18.25%
runner C: 9.35 = 10.69%
runner D: 6.35 = 15.75%
The total implied probability comes to 100.55% showing a slight advantage to the bookmaker and thus preventing me from using a dutching system to make this +EV.
However, I earlier placed a $2 bet on runner A at odds of 2.6 (showing a $3.20 profit if this runner wins). This means I can now use a dutching system to make this +EV in all 4 outcomes. (I threw some bets into the spreadsheet until I came up with A=18, B=7, C=4 & D=6 which appears to work.)
What formula should I use to work out the best bet sizes to extract most profit from this situation???
(I am guessing it is something to do with dividing the $3.20 by the .55 overround but am getting lost somewhere....)
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spoonitnow
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Straight Flush
Join Date: Sep 2005
Location: IRC Chat Room
Posts: 5,406
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What the fuck is dutching? This is interesting to me.
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Quote:
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Originally Posted by Ripptyde
I only have 2 simple rules when I am coaching a new student.
Rule # 1: don't ask questions
Rule # 2: don't ask questions
I have no interest in discussing strategy with a protege'. Your job is to remain quiet and listen. I have a very systematic approach that I will share with the right candidate and I promise that I will turn you into a force of nature and show you elements of the game of poker that you never knew existed.
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HiLo
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Flush
Join Date: May 2007
Posts: 250
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dutching is where you place a bet on every runner with the stakes adjusted so that all outcomes show a profit. (Named after Al Capone's accountant reputedly)
In order to successfully apply a dutching system the total implied probability must be <100
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spoonitnow
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Straight Flush
Join Date: Sep 2005
Location: IRC Chat Room
Posts: 5,406
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Quote:
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Originally Posted by HiLo
dutching is where you place a bet on every runner with the stakes adjusted so that all outcomes show a profit. (Named after Al Capone's accountant reputedly)
In order to successfully apply a dutching system the total implied probability must be <100
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Gotcha.
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Quote:
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Originally Posted by Ripptyde
I only have 2 simple rules when I am coaching a new student.
Rule # 1: don't ask questions
Rule # 2: don't ask questions
I have no interest in discussing strategy with a protege'. Your job is to remain quiet and listen. I have a very systematic approach that I will share with the right candidate and I promise that I will turn you into a force of nature and show you elements of the game of poker that you never knew existed.
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Galapogos
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4-of-a-Kind
Join Date: Jun 2005
Location: The Loser's Lounge
Posts: 2,322
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Dutching sounds dirty.
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Quote:
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Originally Posted by sauce123
I don't get why you insist on stacking off with like jack high all the time.
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mrickett
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Administrator
Administrator
Join Date: Dec 2007
Location: Ishpeming, Michigan.
Posts: 116
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wow I just finished my probability and statistics course 3 months ago and already this makes no sense. The second I left that class room for the last time I left my knowledge there!
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biondino
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4-of-a-Kind
Join Date: Apr 2005
Location: Putney, UK; Full Tilt,Mansion; $50 NL and PL; $13 and $16 SNGs at Stars
Posts: 3,170
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Is the technical term "arbitrage"?
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Numbr2intheWorld
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Moderator
Join Date: Aug 2006
Posts: 3,561
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sorry i don't know.
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euphoricism
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4-of-a-Kind
Join Date: Mar 2005
Location: Your place or my place
Posts: 3,610
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Quote:
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Originally Posted by biondino
Is the technical term "arbitrage"?
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Basically the same thing, I think. Betting both sides with a gaurenteed +EV result as in sportsbetting.
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HiLo
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Flush
Join Date: May 2007
Posts: 250
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Thanks to those who showed an interest:
I have since confirmed that you can't increase the equity by backing runner A at the new odds.
If I wish to guarantee a win by dutching the other 3 selections that is fine, but the return will always be limited by the earlier bet.
i.e. bet sizes should be:
B = (5.2 / 5.48) = 0.95
C = (5.2 / 9.35) = 0.96
D = (5.2/6.35) = 0.82
producing a guaranteed return of $0.88 on any outcome.
If i add to runner A at the new odds then dutch it across the other 3 I will return less than $0.88.
Wish I could express this in terms of algebra though...
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swiggidy
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4-of-a-Kind
Join Date: Sep 2005
Location: Waiting in the shadows ...
Posts: 3,777
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I never tried to do the math because I haven't been that bored.
Intuition tells me that if the sum of the odds is > 100% it doesn't really matter how you spread the money profit wise. You could minimize variance, but eV is typically eV in a non-decision based environment.
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