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Pyroxene's Stupid Poker Challenge

  
 
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Pyroxene
Old 05-02-2005, 12:31 AM     Post subject: Pyroxene's Stupid Poker Challenge #1 (permalink)  
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Pyroxene
The challenge:

Create a Texas Hold'em hand deal such that if all the players go to the river there is one hand that can neither win nor tie any boards.

I fooled around with it a few minutes and I have a 9 way deal where one hand has 0 wins and 0 ties. Doing it with fewer players would be a bonus.

EDIT: And it has to be only one hand that has no possible EV. Having two hands where neither has any EV does not satisfy the challenge.
Pyroxene
 
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FishMagician
Old 05-02-2005, 01:16 AM #2 (permalink)  
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Hand 1 - 2s 2h
Hand 2 - 4h 3s
Hand 3 - 6c 5d
Hand 4 - 8h 7s
Hand 5 - Tc 9d
Hand 6 - Qh Js
Hand 7 - Ac Kd
Hand 8 - 2c 3h
Hand 9 - 2d 3d

Doesn't matter what the last 2 hands are as long as they each have a 2.

Hand 1 can't win or tie.
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Greedo017
Old 05-02-2005, 02:29 AM #3 (permalink)  
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 that board can tie, any straight 10-a ties
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face
Old 05-02-2005, 02:50 AM #4 (permalink)  
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face
Quote:
Originally Posted by FishMagician
Hand 1 - 2s 2h
Hand 2 - 4h 3s
Hand 3 - 6c 5d
Hand 4 - 8h 7s
Hand 5 - Tc 9d
Hand 6 - Qh Js
Hand 7 - Ac Kd
Hand 8 - 2c 3h
Hand 9 - 2d 3d

Doesn't matter what the last 2 hands are as long as they each have a 2.

Hand 1 can't win or tie.
Ad 3s 4c 5h 10d -- Hands 1 8 and 9 tie.
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FishMagician
Old 05-02-2005, 02:59 AM #5 (permalink)  
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hmmmm......pokerstove had 0% 0%

you guys are both right though. I will try again.
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FishMagician
Old 05-02-2005, 03:35 AM #6 (permalink)  
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Ok pretty sure I really got it this time

Hand 1 - 2d 2c
Hand 2 - 3d 2h
Hand 3 - 4c 2s
Hand 4 - Ts Th
Hand 5 - Td Tc
Hand 6 - 7h 6s
Hand 7 - 9c 8d
Hand 8 - Ad Ac
Hand 9 - As Ah

Hand 1 no wins no ties.
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Greedo017
Old 05-02-2005, 04:30 AM #7 (permalink)  
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 your new one works fishmagician. can you find one with 8 hands? this is tough, i couldn't even come up with that one.
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Greedo017
Old 05-02-2005, 04:35 AM #8 (permalink)  
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 1 2d 2h
2 2c 3s
3 2s 4d
4 Ts Th
5 Td Tc
6 5h 5s
7 5c 5d
8 Ad Ac
9 Ah As
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ekillian
Old 05-02-2005, 04:36 AM #9 (permalink)  
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Quote:
Originally Posted by FishMagician
Ok pretty sure I really got it this time

Hand 1 - 2d 2c
Hand 2 - 3d 2h
Hand 3 - 4c 2s
Hand 4 - Ts Th
Hand 5 - Td Tc
Hand 6 - 7h 6s
Hand 7 - 9c 8d
Hand 8 - Ad Ac
Hand 9 - As Ah

Hand 1 no wins no ties.
BOARD: 3h-4h-5d-6c-7c
Board ties. Does that count?
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Greedo017
Old 05-02-2005, 04:40 AM #10 (permalink)  
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 no, 89 wins
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ekillian
Old 05-02-2005, 04:47 AM #11 (permalink)  
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ahhh [dumb]didn't think about that. [/dumb]
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Pyroxene
Old 05-02-2005, 07:03 PM #12 (permalink)  
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FishMagician and Greddo017 met the challenge! My answer was similar to Greedo's; while FishMagician used a different method of accounting for board straights.

Bonus points to anyone that can do it in less than 9 hands.
Pyroxene
 
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dalecooper
Old 05-02-2005, 07:54 PM #13 (permalink)  
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Here's a similar dilemma: can anyone think of a group of starting hands at a full ring (10 handed) where a player with pocket aces couldn't possibly win? (He is however allowed to tie.) I cheated a little bit to make this happen, but I'm curious if anyone else can come up with a better solution.
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mattperkins26
Old 05-02-2005, 08:10 PM #14 (permalink)  

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I think I have it. *crosses fingers* 2d Kc never wins.

Hand 1 - 2d Kc
Hand 2 - 2h 6d
Hand 3 - 2c Ah
Hand 4 - 7s 8c
Hand 5 - 9d Tc
Hand 6 - Jh Qs
Hand 7 - Kd Ad
Hand 8 - As Ac
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dalecooper
Old 05-02-2005, 08:13 PM #15 (permalink)  
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Quote:
Originally Posted by mattperkins26
I think I have it. *crosses fingers* 2d Kc never wins.

Hand 1 - 2d Kc
Hand 2 - 2h 6d
Hand 3 - 2s 7c
Hand 4 - 2h Ah
Hand 5 - 9d Tc
Hand 6 - Jh Qs
Hand 7 - Kc Ad
Hand 8 - As Ac
You've got two repeat cards there (Kc and 2h)...
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mattperkins26
Old 05-02-2005, 08:19 PM #16 (permalink)  

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mattperkins26
Edited above, but here it is again


Hand 1 - 2d Kc
Hand 2 - 2h 6d
Hand 3 - 2c Ah
Hand 4 - 7s 8c
Hand 5 - 9d Tc
Hand 6 - Jh Qs
Hand 7 - Kd Ad
Hand 8 - As Ac
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Pyroxene
Old 05-02-2005, 08:23 PM #17 (permalink)  
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Pyroxene
Quote:
Originally Posted by mattperkins26
I think I have it. *crosses fingers* 2d Kc never wins.

Hand 1 - 2d Kc
Hand 2 - 2h 6d
Hand 3 - 2c Ah
Hand 4 - 7s 8c
Hand 5 - 9d Tc
Hand 6 - Jh Qs
Hand 7 - Kd Ad
Hand 8 - As Ac
Matt,

The 2d Kc hand can win with a K2 on the board for two pair. Running it through one of the calculators on the net, Hand 1 can win 6949 ways and tie 1206 ways. I think most of the ties are places where the other two Kings fall and then the boar pairs up for a Kings over X full house.
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Pyroxene
Old 05-02-2005, 08:24 PM #18 (permalink)  
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Pyroxene
Quote:
Originally Posted by dalecooper
Here's a similar dilemma: can anyone think of a group of starting hands at a full ring (10 handed) where a player with pocket aces couldn't possibly win? (He is however allowed to tie.) I cheated a little bit to make this happen, but I'm curious if anyone else can come up with a better solution.
Ah Ad
Ac As
Kh Qh
Jh Th
9h 8h
7h 6h
Kd Qd
Jd Td
9d 8d
7d 6d
Pyroxene
 
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dalecooper
Old 05-02-2005, 08:47 PM #19 (permalink)  
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Ah Ad
Ac As
Kh Qh
Jh Th
9h 8h
7h 6h
Kd Qd
Jd Td
9d 8d
7d 6d[/quote]

Excellent. Mine was similar but involved a lot of pocket pairs using up the hearts and diamonds. Same effect I guess.
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bigg_nate
Old 05-02-2005, 11:34 PM #20 (permalink)  
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I'm probably missing something, but does this do it with 7 hands?

2c 2s (dead)
2d 2h
Ac As
Ad Ah
8d 8h
7c 8s
7s 8c

- Nate
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Greedo017
Old 05-03-2005, 02:16 AM #21 (permalink)  
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 hmm, i wonder if that one counts. Original rules said you can't have two of the same hand, but only one of the pairs of two's is dead, the other wins sometimes
i betcha that i got something you ain't got, that's called courage, it don't come from no liquor bottle, it ain't scotch
 
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bigg_nate
Old 05-03-2005, 03:34 AM #22 (permalink)  
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Quote:
Originally Posted by Greedo017
hmm, i wonder if that one counts. Original rules said you can't have two of the same hand, but only one of the pairs of two's is dead, the other wins sometimes
In that case, how about

2c 2s
Ac As
Ad Ah
8c 8s
8d 8h
2d 7c
2h 7s

More evidence that you should never go all-in against the almighty 27o!

- Nate
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bigg_nate
Old 05-03-2005, 03:46 AM #23 (permalink)  
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bigg_nate
Or, if you insist on NO two hands being the same:

2s 2c
As Ac
8s 8c
Ad 8h
Ah 7s
2h 8d
2d 7c

- Nate
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