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Posted: Tue, 27 Jun 2006, 6:24pm Post subject: Comparing odds. |
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Two Pair

Joined: 08 Jun 2006
Posts: 38 WPP: 52
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I was reading this article - http://www.thepokerforum.com/pokermath2.htm
"So that makes the ratio of cards you don't need to need 35 to 12 or around 3 to 1. You would have to put 35/12 into its simplest form and its around 3/1 not exact (the exact figure is 2.916 repeating). Round that off to 3 to 1. The pot would have to be at least 3 times the size of the bet. "
How is that 3-1? What math did he do to figure out it was 3-1? |
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Posted: Wed, 28 Jun 2006, 1:51am Post subject: |
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Full House

Joined: 12 Jan 2005
Posts: 1461 WPP: 122
Location: wearing the honors of honor and whatnot
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my teacher just explained this to us the other day for a totally unrelated purpose but it works here. hope its clear.
think of it in parts, the smaller number being one part
47/12 = 4 = 1 part
47/35= 12 = 3 parts
so, 35 is 3 parts, 12 is 1 part, so 3:1.
I think an easier way to think of it is this. You have 12 outs. 12 x 2 + fudging a little is 25%. So you are going to win this pot 25% of the time and lose it 75% of the time. so, 25% is 1 part, 75% is 3 parts, 3:1.
if you don't think that's true or can't take it on intuition alone, consider it this way. 25% to win, 75% to lose. If you ran this hand 4 times, with the expected 3 wins and 1 loss, what does the pot need to be to break even? Let's say the pot is 300 and you need to call 100. 4 run throughs of calling. you spent 400 dollars calling those 4 times. you won once, and got the 300+100 so 400 dollar pot, and you've just broken even. |
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Posted: Wed, 28 Jun 2006, 7:31pm Post subject: |
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Two Pair

Joined: 08 Jun 2006
Posts: 38 WPP: 52
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Hmm, still a bit foggy.
Would you mind doing a few more examples please?
A question about pot odds, why do you calculate them?
If you have a good hand, your going to call/raise regardless of the pot odds right?
Same with a bad one, check/fold? What's the point of calculating them? I really don't decide my calls based on math, nor pot odds.
But I am trying to get them all down for when I need them. The people I play with know nothing about pot odds, outs, etc... |
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Posted: Wed, 28 Jun 2006, 9:33pm Post subject: |
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4-of-a-Kind

Joined: 15 Sep 2005
Posts: 2871 WPP: 109
Location: searching for something...
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| CaseAce wrote: | Hmm, still a bit foggy.
Would you mind doing a few more examples please? | Why don't you try? You are 80% to win, what are the odds of winning?
| CaseAce wrote: | | A question about pot odds, why do you calculate them? | Lets play a coin-flip game.
I pay you $2 if heads come, you pay me $1 if tails come. Do you play this game?
I pay you $1 if heads come, you pay me $2 if tails come. Do you play this game?
| CaseAce wrote: | | If you have a good hand, your going to call/raise regardless of the pot odds right? | If you are best then you want to make a bet that if your opponent calls, will be making a mistake.
| CaseAce wrote: | | Same with a bad one, check/fold? | What's bad? 93o on a AKQ flop, or QJ on the same flop?
| CaseAce wrote: | | What's the point of calculating them? I really don't decide my calls based on math, nor pot odds. | Given above, pot is 100. Do you call a 10 bet with 93o? What about QJ? What about a 100 bet with QJ? Odds allow an analytical answer to these questions.
| CaseAce wrote: | | But I am trying to get them all down for when I need them. The people I play with know nothing about pot odds, outs, etc... | I briefly looked for an odds post but couldn't find one. You will own these people if you put in the time to learn.
I tried to explain odds to a friend at work. One day he won our little tourney and told me that using odds messed up his game, and that playing by feeling was better. He rivered a winning card at least 5 times in that game. It will be awhile before he wins again. Do you see why? |
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Posted: Wed, 28 Jun 2006, 9:38pm Post subject: |
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4-of-a-Kind

Joined: 15 Sep 2005
Posts: 2871 WPP: 109
Location: searching for something...
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| swiggidy wrote: | | I briefly looked for an odds post but couldn't find one. You will own these people if you put in the time to learn. | I briefly looked for a general odds post. If you want to know how they are used click on any random thread and there is at least a 50% chance (1:1 odds) that odds are discussed. |
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Posted: Wed, 28 Jun 2006, 10:21pm Post subject: |
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Two Pair

Joined: 08 Jun 2006
Posts: 38 WPP: 52
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"Why don't you try? You are 80% to win, what are the odds of winning?"
4-1? |
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Posted: Thu, 29 Jun 2006, 5:43am Post subject: |
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4-of-a-Kind

Joined: 15 Sep 2005
Posts: 2871 WPP: 109
Location: searching for something...
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Posted: Thu, 29 Jun 2006, 4:06pm Post subject: |
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Full House

Joined: 12 Jan 2005
Posts: 1461 WPP: 122
Location: wearing the honors of honor and whatnot
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after you get a little experience too, implied odds let you fudge a little. calling a halfpot bet with a straight draw might not be correct, but you're often going to make up for it on the next hand.
so just remember, outs x 2 = % to hit an out per card to come, and then think, well this bet is probably good/bad/ugly for me to call given my outs, and the odds of me getting paid off if i hit are good/bad/ugly, so i should do x. |
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Posted: Thu, 29 Jun 2006, 4:45pm Post subject: |
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Two Pair

Joined: 08 Jun 2006
Posts: 38 WPP: 52
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I know how to find out the pot odds, and outs and stuff. I just don't know how to make the outs into ratios...
Theres 120 in the pot, someone bets 20 into it, the pot odds are 7-1 right? |
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Posted: Thu, 29 Jun 2006, 4:55pm Post subject: |
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Full House

Joined: 12 Jan 2005
Posts: 1461 WPP: 122
Location: wearing the honors of honor and whatnot
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Posted: Thu, 29 Jun 2006, 5:45pm Post subject: |
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4-of-a-Kind

Joined: 15 Sep 2005
Posts: 2871 WPP: 109
Location: searching for something...
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| CaseAce wrote: | | Theres 120 in the pot, someone bets 20 into it, the pot odds are 7-1 right? | You mean someone bets 20 so now the pot is 140 and it cost you 20 to call correct?
| CaseAce wrote: | | I know how to find out the pot odds, and outs and stuff. I just don't know how to make the outs into ratios... | Lets say you see the flop and decide you have 6 outs. That means 6 cards help, and conversly 41 cards don't help. Your ratio is 6:41. Divide both sides by 6, the ratio is also 1:6.8, round to 1:7.
The other way people do it is say 6 out of 47 cards help, so you'll catch your card 13% of the time. So the ratio is 13%:87%. Divide both sides by 13% and we get 1:6.7 (note it's off by .1 because of rounding errors). |
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Posted: Thu, 29 Jun 2006, 8:12pm Post subject: |
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Two Pair

Joined: 08 Jun 2006
Posts: 38 WPP: 52
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The other way people do it is say 6 out of 47 cards help, so you'll catch your card 13% of the time. So the ratio is 13%:87%. Divide both sides by 13% and we get 1:6.7 (note it's off by .1 because of rounding errors).
I understand the ratios now, thanks. But, you confused me with the 6 out of 47 cards left. Is that right after the flop? And the turns about to hit? I have been using the 4, 2 rule. So wouldn't I multiply the 6 by 4?
Or have I been doing it wrong the whole time?
And for my other post, yeah the pot is 120 and my opponent bet 20 into it. |
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Posted: Thu, 29 Jun 2006, 8:58pm Post subject: |
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4-of-a-Kind

Joined: 15 Sep 2005
Posts: 2871 WPP: 109
Location: searching for something...
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| CaseAce wrote: | I understand the ratios now, thanks. But, you confused me with the 6 out of 47 cards left. Is that right after the flop? And the turns about to hit? I have been using the 4, 2 rule. So wouldn't I multiply the 6 by 4?
Or have I been doing it wrong the whole time? | I think this is an idea from limit holdem. For example, if you bet from the button, you might get checked too on the turn, "buying a free card". In that case it would be 6*4 because you would have two chances to catch one of your six cards. If you are facing an aggro NL opponent then you will not get the river card without paying again, so you should be using the 6 * 2 rule (unless you go all-in, then you get 2 cards).
So to answer your question, "It depends". |
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Posted: Thu, 29 Jun 2006, 9:31pm Post subject: |
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Two Pair

Joined: 08 Jun 2006
Posts: 38 WPP: 52
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So, if you have decided you weren't going to put another chip in the pot unless you made your hand, going to the turn, you would multiply by 2. I get it.
Now let me try.
Pot : 375. Someone bets 90. Pot is now 465.
Pot odds are...around 5-1?
I have 78 of hearts, flop is 9,10,A rainbow. I have 8 outs. 8*4=32%
Would it be 32%-68%? What would that ratio become?
Btw, I really appreciate you coming back and posting and helping me out. Thanks alot. |
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Posted: Thu, 29 Jun 2006, 9:38pm Post subject: |
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Full House

Joined: 19 May 2006
Posts: 722 WPP: 43
Location: Philly
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http://casinogambling.about.com/library/weekly/aa050103.htm
The Rule of Four -Two.
"The rule of four-two, as I like to call it, is an easier way to figure the odds for any situation where you know your outs. It is not completely accurate but it will give you a quick "ballpark" figure of your chances for making a hand. Here is how it works.
With two cards to come after the flop you multiply your number of outs by four. With one card to come after the turn, you multiply your number of outs by two. This will give you a quick figure to work with. If you have a four-card flush after the flop you have nine outs. With two cards to come, you multiply the nine by four and you get 36 percent chance of making the flush. The chart shows the true odds at 35 percent. With one card to come you multiply nine by two and get 18 percent. The chart shows that the true figure is 19.6. It is not completely accurate but it is pretty close, and it is an easy calculation to do in your head." |
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Posted: Thu, 29 Jun 2006, 11:12pm Post subject: |
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Two Pair

Joined: 08 Jun 2006
Posts: 38 WPP: 52
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Alright, I can safly say that I think I can get the pot odds and outs pretty easily now.
But converting percentages to ratios, is something I hate, and no nothing about.
Did I do the math right in my post before Harry's?
I'm gonna take a stab and say 32%-68% would become...
2.1-1? And the pot odds are 5-1.
Which should be higher to mathematically make a right call? |
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Posted: Thu, 29 Jun 2006, 11:20pm Post subject: |
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4-of-a-Kind

Joined: 15 Mar 2006
Posts: 2616 WPP: 84
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| You want to have a better chance at winning than you have to pay.. so if you have to pay 2:1 for a 5:1 chance to win, not good. (unless implied odds make up for it) |
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Posted: Thu, 29 Jun 2006, 11:40pm Post subject: |
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Two Pair

Joined: 08 Jun 2006
Posts: 38 WPP: 52
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So, I was right with 2.1?
So I want my outs ratio to be high than my pot ratio.
Should it be a certain amount higher? Or can it be like just slightly over it, and mathematically it would be a right call? |
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Posted: Fri, 30 Jun 2006, 12:53am Post subject: |
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4-of-a-Kind

Joined: 15 Mar 2006
Posts: 2616 WPP: 84
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If the outs ratio is equal to or higher than the pot ratio (to use your terms), then it's basically an auto-call. This is given that you WILL win the pot if you hit your outs ofcourse, but in the case of flush or straight draws this is usually so.
For example, by the turn, the pot is $10, and you have a flush draw.. so 5.5:1 or something to hit the river. Opponent bets $2.. you have to call 6:1, so this is an auto-call.
Now let's say he bets $4. That like 3.5:1 to call.. so it's not an auto-call.. but if you think you can make some more money if you hit on the river, then you can consider calling anyway. Poker is all about estimating these implied odds, that is why I mention it here in conjunction with pot odds. |
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Posted: Fri, 30 Jun 2006, 5:42am Post subject: |
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4-of-a-Kind

Joined: 15 Sep 2005
Posts: 2871 WPP: 109
Location: searching for something...
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| Harry wrote: | | With two cards to come after the flop you multiply your number of outs by four. With one card to come after the turn, you multiply your number of outs by two. | Right, my point was...
Just because your're on the flop, doesn't mean you can multiply your outs by 4. If you are going all-in, are playing a weak passive player, or even a solid player whom you know will check to you on the turn, then yes you can multiply by four.
If you're OOP against a solid player, and they will bet on the turn if checked to. Now you have to figure that you need the next card to make your hand, if it doesn't then you're done. In this case, even though it's on the flop you essentially have one card to come.
| CaseAce wrote: | | So, I was right with 2.1? | Yes this is correct. Note again, 32:68 is a ratio (of percentages), 15:32 is a ratio (of cards), 1:2.1 is a ratio (simplified for perspective). It's all about simplifying fractions.
| CaseAce wrote: | | Btw, I really appreciate you coming back and posting and helping me out. Thanks alot. | yw |
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Posted: Fri, 30 Jun 2006, 9:14am Post subject: |
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Two Pair

Joined: 08 Jun 2006
Posts: 38 WPP: 52
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I think I got it down now.
Pot is 1000, someone bet 500 into it. Pots now 1500, my pot odds are 3-1.
I have a flush draw on the flop. 9 outs * 4 = 36%
36%-64%
1.7-1?
I should fold? My pot odds are lower than my outs ratio. Right? |
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Posted: Fri, 30 Jun 2006, 9:27am Post subject: |
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4-of-a-Kind

Joined: 15 Sep 2005
Posts: 2871 WPP: 109
Location: searching for something...
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| CaseAce wrote: | Pot is 1000, someone bet 500 into it. Pots now 1500, my pot odds are 3-1.
I have a flush draw on the flop. 9 outs * 4 = 36%
36%-64%
1.7-1? | 1-1.7 (just being anal)
| CaseAce wrote: | | I should fold? My pot odds are lower than my outs ratio. Right? | Here you should call. We'll round your odds to 1:2, so you win once, and loose twice. When you win you get 1500 (don't count your own money you are adding). When you loose twice it's 2*500 = 1000. So making this call yields 1500 - 1000 = +500, which is good.
Mathematically this is a fine example, but practically it isn't. The river card may not be free, the odds of you hitting your flush on the turn is 9 * 2 = 18%, which is about 1:4.
Now you win 1500 once, loose 500 4 times. 1500 - 2000 = -500, which is bad. |
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Posted: Fri, 30 Jun 2006, 9:39am Post subject: |
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